# Solve Using the Square Root Property x^2-5x-10=0 x2-5x-10=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=-5, and c=-10 into the quadratic formula and solve for x.
5±(-5)2-4⋅(1⋅-10)2⋅1
Simplify.
Simplify the numerator.
Raise -5 to the power of 2.
x=5±25-4⋅(1⋅-10)2⋅1
Multiply -10 by 1.
x=5±25-4⋅-102⋅1
Multiply -4 by -10.
x=5±25+402⋅1
Add 25 and 40.
x=5±652⋅1
x=5±652⋅1
Multiply 2 by 1.
x=5±652
x=5±652
Simplify the expression to solve for the + portion of the ±.
Simplify the numerator.
Raise -5 to the power of 2.
x=5±25-4⋅(1⋅-10)2⋅1
Multiply -10 by 1.
x=5±25-4⋅-102⋅1
Multiply -4 by -10.
x=5±25+402⋅1
Add 25 and 40.
x=5±652⋅1
x=5±652⋅1
Multiply 2 by 1.
x=5±652
Change the ± to +.
x=5+652
x=5+652
Simplify the expression to solve for the – portion of the ±.
Simplify the numerator.
Raise -5 to the power of 2.
x=5±25-4⋅(1⋅-10)2⋅1
Multiply -10 by 1.
x=5±25-4⋅-102⋅1
Multiply -4 by -10.
x=5±25+402⋅1
Add 25 and 40.
x=5±652⋅1
x=5±652⋅1
Multiply 2 by 1.
x=5±652
Change the ± to -.
x=5-652
x=5-652
The final answer is the combination of both solutions.
x=5+652,5-652
The result can be shown in multiple forms.
Exact Form:
x=5+652,5-652
Decimal Form:
x=6.53112887…,-1.53112887…
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