Solve using the Square Root Property x^2-5x-4=0

Math
x2-5x-4=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=-5, and c=-4 into the quadratic formula and solve for x.
5±(-5)2-4⋅(1⋅-4)2⋅1
Simplify.
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Simplify the numerator.
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Raise -5 to the power of 2.
x=5±25-4⋅(1⋅-4)2⋅1
Multiply -4 by 1.
x=5±25-4⋅-42⋅1
Multiply -4 by -4.
x=5±25+162⋅1
Add 25 and 16.
x=5±412⋅1
x=5±412⋅1
Multiply 2 by 1.
x=5±412
x=5±412
Simplify the expression to solve for the + portion of the ±.
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Simplify the numerator.
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Raise -5 to the power of 2.
x=5±25-4⋅(1⋅-4)2⋅1
Multiply -4 by 1.
x=5±25-4⋅-42⋅1
Multiply -4 by -4.
x=5±25+162⋅1
Add 25 and 16.
x=5±412⋅1
x=5±412⋅1
Multiply 2 by 1.
x=5±412
Change the ± to +.
x=5+412
x=5+412
Simplify the expression to solve for the – portion of the ±.
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Simplify the numerator.
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Raise -5 to the power of 2.
x=5±25-4⋅(1⋅-4)2⋅1
Multiply -4 by 1.
x=5±25-4⋅-42⋅1
Multiply -4 by -4.
x=5±25+162⋅1
Add 25 and 16.
x=5±412⋅1
x=5±412⋅1
Multiply 2 by 1.
x=5±412
Change the ± to -.
x=5-412
x=5-412
The final answer is the combination of both solutions.
x=5+412,5-412
The result can be shown in multiple forms.
Exact Form:
x=5+412,5-412
Decimal Form:
x=5.70156211…,-0.70156211…
Solve using the Square Root Property x^2-5x-4=0

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