Solve Using the Square Root Property x^2-5x=-6

Math
x2-5x=-6
Move 6 to the left side of the equation by adding it to both sides.
x2-5x+6=0
Factor x2-5x+6 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 6 and whose sum is -5.
-3,-2
Write the factored form using these integers.
(x-3)(x-2)=0
(x-3)(x-2)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-3=0
x-2=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-3=0
Add 3 to both sides of the equation.
x=3
x=3
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x-2=0
Add 2 to both sides of the equation.
x=2
x=2
The final solution is all the values that make (x-3)(x-2)=0 true.
x=3,2
Solve Using the Square Root Property x^2-5x=-6

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