Solve Using the Square Root Property x^2=-5x

$x^{2} = - 5 x$

Add $5 x$ to both sides of the equation.

$x^{2} + 5 x = 0$

Factor $x$ out of $x^{2} + 5 x$ .

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Factor $x$ out of $x^{2}$ .

$x \cdot x + 5 x = 0$

Factor $x$ out of $5 x$ .

$x \cdot x + x \cdot 5 = 0$

Factor $x$ out of $x \cdot x + x \cdot 5$ .

$x (x + 5) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 5 = 0$

Set the first factor equal to $0$ .

$x = 0$

Set the next factor equal to $0$ and solve.

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Set the next factor equal to $0$ .

$x + 5 = 0$

Subtract $5$ from both sides of the equation.

$x = - 5$

The final solution is all the values that make $x (x + 5) = 0$ true.

$x = 0, - 5$

Solve Using the Square Root Property x^2=-5x

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