Solve Using the Square Root Property x^2+6x-27=(x-3)

Math
x2+6x-27=(x-3)
Move all terms containing x to the left side of the equation.
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Subtract x from both sides of the equation.
x2+6x-27-x=-3
Subtract x from 6x.
x2+5x-27=-3
x2+5x-27=-3
Move 3 to the left side of the equation by adding it to both sides.
x2+5x-27+3=0
Add -27 and 3.
x2+5x-24=0
Factor x2+5x-24 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -24 and whose sum is 5.
-3,8
Write the factored form using these integers.
(x-3)(x+8)=0
(x-3)(x+8)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-3=0
x+8=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-3=0
Add 3 to both sides of the equation.
x=3
x=3
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x+8=0
Subtract 8 from both sides of the equation.
x=-8
x=-8
The final solution is all the values that make (x-3)(x+8)=0 true.
x=3,-8
Solve Using the Square Root Property x^2+6x-27=(x-3)

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