Solve using the Square Root Property x^2=6x-8

Math
x2=6x-8
Subtract 6x from both sides of the equation.
x2-6x=-8
Move 8 to the left side of the equation by adding it to both sides.
x2-6x+8=0
Factor x2-6x+8 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 8 and whose sum is -6.
-4,-2
Write the factored form using these integers.
(x-4)(x-2)=0
(x-4)(x-2)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-4=0
x-2=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-4=0
Add 4 to both sides of the equation.
x=4
x=4
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x-2=0
Add 2 to both sides of the equation.
x=2
x=2
The final solution is all the values that make (x-4)(x-2)=0 true.
x=4,2
Solve using the Square Root Property x^2=6x-8

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