Solve using the Square Root Property x^2+7x+13=1

Math
x2+7x+13=1
Move 1 to the left side of the equation by subtracting it from both sides.
x2+7x+13-1=0
Subtract 1 from 13.
x2+7x+12=0
Factor x2+7x+12 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 12 and whose sum is 7.
3,4
Write the factored form using these integers.
(x+3)(x+4)=0
(x+3)(x+4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x+3=0
x+4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x+3=0
Subtract 3 from both sides of the equation.
x=-3
x=-3
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x+4=0
Subtract 4 from both sides of the equation.
x=-4
x=-4
The final solution is all the values that make (x+3)(x+4)=0 true.
x=-3,-4
Solve using the Square Root Property x^2+7x+13=1

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