Solve using the Square Root Property x(x-3)=28

Math
x(x-3)=28
Simplify x(x-3).
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Apply the distributive property.
x⋅x+x⋅-3=28
Simplify the expression.
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Multiply x by x.
x2+x⋅-3=28
Move -3 to the left of x.
x2-3x=28
x2-3x=28
x2-3x=28
Move 28 to the left side of the equation by subtracting it from both sides.
x2-3x-28=0
Factor x2-3x-28 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -28 and whose sum is -3.
-7,4
Write the factored form using these integers.
(x-7)(x+4)=0
(x-7)(x+4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-7=0
x+4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-7=0
Add 7 to both sides of the equation.
x=7
x=7
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x+4=0
Subtract 4 from both sides of the equation.
x=-4
x=-4
The final solution is all the values that make (x-7)(x+4)=0 true.
x=7,-4
Solve using the Square Root Property x(x-3)=28

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