Solve Using the Square Root Property x(x-4)=12

Math
x(x-4)=12
Simplify x(x-4).
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Apply the distributive property.
x⋅x+x⋅-4=12
Simplify the expression.
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Multiply x by x.
x2+x⋅-4=12
Move -4 to the left of x.
x2-4x=12
x2-4x=12
x2-4x=12
Move 12 to the left side of the equation by subtracting it from both sides.
x2-4x-12=0
Factor x2-4x-12 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -12 and whose sum is -4.
-6,2
Write the factored form using these integers.
(x-6)(x+2)=0
(x-6)(x+2)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-6=0
x+2=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-6=0
Add 6 to both sides of the equation.
x=6
x=6
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x+2=0
Subtract 2 from both sides of the equation.
x=-2
x=-2
The final solution is all the values that make (x-6)(x+2)=0 true.
x=6,-2
Solve Using the Square Root Property x(x-4)=12

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