# Solve using the Square Root Property x(x-6)=40 x(x-6)=40
Simplify x(x-6).
Apply the distributive property.
x⋅x+x⋅-6=40
Simplify the expression.
Multiply x by x.
x2+x⋅-6=40
Move -6 to the left of x.
x2-6x=40
x2-6x=40
x2-6x=40
Move 40 to the left side of the equation by subtracting it from both sides.
x2-6x-40=0
Factor x2-6x-40 using the AC method.
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -40 and whose sum is -6.
-10,4
Write the factored form using these integers.
(x-10)(x+4)=0
(x-10)(x+4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-10=0
x+4=0
Set the first factor equal to 0 and solve.
Set the first factor equal to 0.
x-10=0
Add 10 to both sides of the equation.
x=10
x=10
Set the next factor equal to 0 and solve.
Set the next factor equal to 0.
x+4=0
Subtract 4 from both sides of the equation.
x=-4
x=-4
The final solution is all the values that make (x-10)(x+4)=0 true.
x=10,-4
Solve using the Square Root Property x(x-6)=40     