Write as a Function of x 5x^2-kx+40=0

$5 x^{2} - k x + 40 = 0$

Move all terms not containing $k$ to the right side of the equation.

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Subtract $5 x^{2}$ from both sides of the equation.

$- k x + 40 = - 5 x^{2}$

Subtract $40$ from both sides of the equation.

$- k x = - 5 x^{2} - 40$

Divide each term by $- 1 x$ and simplify.

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Divide each term in $- k x = - 5 x^{2} - 40$ by $- 1 x$ .

$\frac{- k x}{- 1 x} = \frac{- 5 x^{2}}{- 1 x} + \frac{- 40}{- 1 x}$

Simplify $\frac{- k x}{- 1 x}$ .

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Dividing two negative values results in a positive value.

$\frac{k x}{x} = \frac{- 5 x^{2}}{- 1 x} + \frac{- 40}{- 1 x}$

Cancel the common factor of $x$ .

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Cancel the common factor.

$\frac{k x}{x} = \frac{- 5 x^{2}}{- 1 x} + \frac{- 40}{- 1 x}$

Divide $k$ by $1$ .

$k = \frac{- 5 x^{2}}{- 1 x} + \frac{- 40}{- 1 x}$

Simplify each term.

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Cancel the common factor of $x^{2}$ and $x$ .

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Factor $x$ out of $- 5 x^{2}$ .

$k = \frac{x (- 5 x)}{- 1 x} + \frac{- 40}{- 1 x}$

Move the negative one from the denominator of $\frac{- 5 x}{- 1}$ .

$k = - 1 \cdot (- 5 x) + \frac{- 40}{- 1 x}$

Rewrite $- 1 \cdot (- 5 x)$ as $- (- 5 x)$ .

$k = - (- 5 x) + \frac{- 40}{- 1 x}$

Multiply $- 5$ by $- 1$ .

$k = 5 x + \frac{- 40}{- 1 x}$

Dividing two negative values results in a positive value.

$k = 5 x + \frac{40}{x}$

To rewrite as a function of $x$ , write the equation so that $k$ is by itself on one side of the equal sign and an expression involving only $x$ is on the other side.

$f (x) = 5 x + \frac{40}{x}$

Write as a Function of x 5x^2-kx+40=0

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