Write as a Function of x x^2+y^2=169

$x^{2} + y^{2} = 169$

Subtract $x^{2}$ from both sides of the equation.

$y^{2} = 169 - x^{2}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{169 - x^{2}}$

The complete solution is the result of both the positive and negative portions of the solution.

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Simplify the right side of the equation.

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Rewrite $169$ as $13^{2}$ .

$y = \pm \sqrt{13^{2} - x^{2}}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 13$ and $b = x$ .

$y = \pm \sqrt{(13 + x) (13 - x)}$

The complete solution is the result of both the positive and negative portions of the solution.

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First, use the positive value of the $\pm$ to find the first solution.

$y = \sqrt{(13 + x) (13 - x)}$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - \sqrt{(13 + x) (13 - x)}$

The complete solution is the result of both the positive and negative portions of the solution.

$y = \sqrt{(13 + x) (13 - x)}$

$y = - \sqrt{(13 + x) (13 - x)}$

$y = \sqrt{(13 + x) (13 - x)}$

$y = - \sqrt{(13 + x) (13 - x)}$

$y = \sqrt{(13 + x) (13 - x)}$

$y = - \sqrt{(13 + x) (13 - x)}$

To rewrite as a function of $x$ , write the equation so that $y$ is by itself on one side of the equal sign and an expression involving only $x$ is on the other side.

$f (x) = \sqrt{(13 + x) (13 - x)}, - \sqrt{(13 + x) (13 - x)}$

Write as a Function of x x^2+y^2=169

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