Write in Exponential Form log base 4 of x=2

$\log_{4} (x) = 2$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 4$ , $x = x$ , and $y = 2$ .

$b = 4$

$x = x$

$y = 2$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$4^{2} = x$

Write in Exponential Form log base 4 of x=2

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