Write the Equation in Standard Form 9-7x=(4x-3)^2+5

$9 - 7 x = {(4 x - 3)}^{2} + 5$

To write an equation in standard form, move each term to the left side of the equation and simplify.

$a x^{2} + b x + c = 0$

Move all the expressions to the left side of the equation.

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Move ${(4 x - 3)}^{2}$ to the left side of the equation by subtracting it from both sides.

$9 - 7 x - {(4 x - 3)}^{2} = 5$

Move $5$ to the left side of the equation by subtracting it from both sides.

$9 - 7 x - {(4 x - 3)}^{2} - 5 = 0$

Simplify.

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Simplify each term.

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Rewrite ${(4 x - 3)}^{2}$ as $(4 x - 3) (4 x - 3)$ .

$9 - 7 x - ((4 x - 3) (4 x - 3)) - 5 = 0$

Expand $(4 x - 3) (4 x - 3)$ using the FOIL Method.

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Apply the distributive property.

$9 - 7 x - (4 x (4 x - 3) - 3 (4 x - 3)) - 5 = 0$

Apply the distributive property.

$9 - 7 x - (4 x (4 x) + 4 x \cdot - 3 - 3 (4 x - 3)) - 5 = 0$

Apply the distributive property.

$9 - 7 x - (4 x (4 x) + 4 x \cdot - 3 - 3 (4 x) - 3 \cdot - 3) - 5 = 0$

Simplify and combine like terms.

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Simplify each term.

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Multiply $x$ by $x$ .

$9 - 7 x - (4 \cdot (4 x^{2}) + 4 x \cdot - 3 - 3 (4 x) - 3 \cdot - 3) - 5 = 0$

Multiply $4$ by $4$ .

$9 - 7 x - (16 x^{2} + 4 x \cdot - 3 - 3 (4 x) - 3 \cdot - 3) - 5 = 0$

Multiply $- 3$ by $4$ .

$9 - 7 x - (16 x^{2} - 12 x - 3 (4 x) - 3 \cdot - 3) - 5 = 0$

Multiply $4$ by $- 3$ .

$9 - 7 x - (16 x^{2} - 12 x - 12 x - 3 \cdot - 3) - 5 = 0$

Multiply $- 3$ by $- 3$ .

$9 - 7 x - (16 x^{2} - 12 x - 12 x + 9) - 5 = 0$

Subtract $12 x$ from $- 12 x$ .

$9 - 7 x - (16 x^{2} - 24 x + 9) - 5 = 0$

Apply the distributive property.

$9 - 7 x - (16 x^{2}) - (- 24 x) - 1 \cdot 9 - 5 = 0$

Simplify.

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Multiply $16$ by $- 1$ .

$9 - 7 x - 16 x^{2} - (- 24 x) - 1 \cdot 9 - 5 = 0$

Multiply $- 24$ by $- 1$ .

$9 - 7 x - 16 x^{2} + 24 x - 1 \cdot 9 - 5 = 0$

Multiply $- 1$ by $9$ .

$9 - 7 x - 16 x^{2} + 24 x - 9 - 5 = 0$

Simplify by adding terms.

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Combine the opposite terms in $9 - 7 x - 16 x^{2} + 24 x - 9 - 5$ .

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Subtract $9$ from $9$ .

$- 7 x - 16 x^{2} + 24 x + 0 - 5 = 0$

Add $- 7 x - 16 x^{2} + 24 x$ and $0$ .

$- 7 x - 16 x^{2} + 24 x - 5 = 0$

Add $- 7 x$ and $24 x$ .

$- 16 x^{2} + 17 x - 5 = 0$

Reorder the polynomial in descending order.

$16 x^{2} - 17 x + 5 = 0$

Write the Equation in Standard Form 9-7x=(4x-3)^2+5

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