Write the Equation in Standard Form y+3=-5(x+1)

$y + 3 = - 5 (x + 1)$

The standard form of a linear equation is $A x + B y = C$ .

Simplify $- 5 (x + 1)$ .

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Apply the distributive property.

$y + 3 = - 5 x - 5 \cdot 1$

Multiply $- 5$ by $1$ .

$y + 3 = - 5 x - 5$

Move all terms containing variables to the left side of the equation.

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Add $5 x$ to both sides of the equation.

$y + 3 + 5 x = - 5$

Move $3$ .

$y + 5 x + 3 = - 5$

Reorder $y$ and $5 x$ .

$5 x + y + 3 = - 5$

Move all terms not containing a variable to the right side of the equation.

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Subtract $3$ from both sides of the equation.

$5 x + y = - 5 - 3$

Subtract $3$ from $- 5$ .

$5 x + y = - 8$

Write the Equation in Standard Form y+3=-5(x+1)

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